Math, asked by sasmita01, 14 days ago

IIf 30 men do a piece of work in 27 days, in what time can 18 men do another piece of work 3 times as great?​

Answers

Answered by AεѕтнεтícᎮѕуcнσ
1

Answer:

30 men can do a piece of work in 27 days, and we know that men* days = total work

So, we can say that the total work = 30*27 = 810 units

Now ATQ, 18 men can do work 3 times greater than 810 units.

i.e., 18 men can do a work 3*810 = 2430 units in x days

Men *days = total work (2430 units)

18 * x = 2430

x = 2430/18 = 135 days

Solution 2:

Let the number of days required to do a work = x

Now, 30 men can do a piece of work in 27 days.

ATQ, if the work gets 3 times, then 18 men can finish the work in how many days.

Now, put the same unit on the same side.

i.e., if the work is the same as previous, then 18 men: 30 men = 27 days: x days

Or, x = (30*27)/ 18

But ATQ, the work gets 3 times greater

So, x = (30*27*3)/ 18 = 2430/18 = 135 days

Hence, 18 men can finish the other work which is 3 times greater than previous work in 135 days.

Answered by abhishek99853
1

Answer:

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Step-by-step explanation:

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