Question

iIf α and β are the zeros of the quadratic polynomial f(x)= x(x-4), find the value of 1/α +1/β -2αβ.​ ​

Answer 1

$\huge\textbf{Good\:Mning}$
$<b>$
Your answer:

The given polynomial is

f (x) = x² - x - 4

Since α and β are the zeros of f (x),

α + β = - (- 1)/1

⇒ α +β = 1 ...(i)

and

αβ = - 4/1 

⇒ αβ = - 4 ...(ii)

Now,

1/α + 1/β - αβ

= (α + β)/(αβ) - (αβ)

= 1/(- 4) - (- 4)

= - 1/4 + 4

= (- 1 + 16)/4

= 15/4

#Hope it will help you.....I think it's correct!!

Answer 2

Answer:

alpha^2-4,alpha+bita=0/1=0

alpha×bita=c/a=-4/1=-4

1/alpha+1/bita-2alpha×bita

bita+alpha/alpha×bita-2alpha×bita

0/-4-2×-4=0+8=8