Question

(iii)
(1 + tan’A) sin A cos A = tan A​

Answer 1

Answer:

Step-by-step explanation:

$L.H.S.$

$=(1+tan^{2}A )\times sinA\times cosA$

$=(sec^{2}A )\times sinA\times cosA$                ∵ $1+tan^{2}A =sec^{2}A$

$=\frac{1}{cos^2 A } \times sinA\times cosA$                    ∵ $sec A = \frac{1}{cos A}$

$=\frac{sinA}{cosA}$

$=tanA$

$=R.H.S.$

Thus Proved.