Question

(iii) 3.011 10” number of N atoms
(iv) 6.022 x 10” number of N, molecules​

Answer 1

3.011×10

23

no. of nitrogen atom at mass of nitrogen =14g

1 mole of nitrogen contains 6.022×10

23

atoms

14g will contains 6.022×10

23

atoms

how,

6.022×10

23

14

g contains 1 atom

∴(

6.022×10

23

14

)×3.011×10

23

=

2

14

=7g of N.

next answer

We know, 1 mole = 6.022 × 1023 Now, to calculate mass, apply the formula: Number of moles(n) = Mass(m)Molarmass(M)Mass(m)Molarmass(M) we can write: Mass(m) = Number of moles (n) × Molar mass of N2 (M) Mass = 1 mol × 28g/mol Mass = 28g Thus, the mass of 6.022 × 1023 atoms of nitrogen is 28gRead more on Sarthaks.com - https://www.sarthaks.com/960131/calculate-the-mass-of-6-022-10-23-n2-molecules