Question

(iii) 49 -2.8x +0.04x2​

Answer 1

$49 - 2.8x + {0.04x}^{2} \\ \\ 49 - 1.4x - 1.4x + {0.04x}^{2} \\ \\ {0.04x}^{2} - 1.4x - 1.4x + 49 \\ \\ \frac{ {4x}^{2} }{100} - \frac{14x}{10} - \frac{14x}{10} + 49 \\ \\ \frac{ {4x}^{2} - 140x - 140x + 4900}{100} \\ \\ ({4x}^{2} - 140x - 140x + 4900) \frac{1}{100} \\ \\ [4x(x - 35) - 140(x - 35)] \frac{1}{100} \\ \\ (4x - 140)(x - 35) \frac{1}{100} \\ \\ (0.04x - 1.4)(x - 35)$

Answer 2

(7-0.2x) (7-0.2x)

Explanation:

it is your answer