iii) (a+b) (2 + i) = b + 1 + (10 + 2a)i
iv) ahi=32-bt12i.
13)
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- a(2+i) + b(2+i) = b+ 1 + 10i + 2ai. 2a+ia +2b +ib =b + 1 + 10i + 2ai. a +ia + b +ib+b /I +ai = 1+10 +2 /2 +2
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