Question

(iii)
A man saved 32 during the first year, 36 in the second year and in
this way he increases his saving by 4 every year. Find in what time his
savings will be 200?​

Answer 1

Answer:

a=32

d=4

an=a+(n-1)d

200=32+(n-1)4

200-32=(n-1)4

168=(n-1)4

168/4=n-1

42=n-1

n=4

Answer 2

On fifth day his saving will be 200.

32+36+40+44+48=200