Question

iii. Calculate the energy of the third Bohr orbit of Li2+ion. (in J/atom unit)

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Answer 1

Answer:

The answer is -0.242×10-¹⁸ J/atom

Explanation:

It was solved by using the formula

Energy of nth orbit = (-2.18×10-¹⁸)/n² J/atom

Energy of 3rd orbit = (-2.18×10-¹⁸)/3² J/atom

=(-0.242×10-¹⁸) J/atom

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