Question

(iii) Calculate the volume of oxygen required for the
complete combustion of 8.8 g of propane (CH).
(Atomic mass : C = 12, O = 16, H = 1, Molar
Volume = 22-4 dm? at stp.)​

Answer 1

Answer:

22.4 litres

Explanation:

44g of propane requires 5 × 22.4 litres of oxygen at STP. 8.8g of propane requires `[5 xx 22.4 xx 8.8]/44` = 22.4 litres.