Science, asked by ansh475120, 1 year ago

(iii) Considering first correlation, complete the second :
Acceleration due to gravity : m/s2 :: Gravitational constant :.................. ​

Answers

Answered by purvapednekar
27

Answer:

gravitational constant = N.m^2/Kg^2

Answered by harendrachoubay
16

The missing unit of gravitational constant =\dfrac{N.m^2}{kg^2}

Explanation:

We have,

Acceleration due to gravity : \dfrac{m}{s^2} :: Gravitational constant : .................. ​

To find, the missing unit of gravitational constant=

The SI unit of acceleration due to gravity is \dfrac{m}{s^2}.

Similarly,

The SI unit of Gravitational constan is \dfrac{N.m^2}{kg^2}

∴ Acceleration due to gravity : \dfrac{m}{s^2} :: Gravitational constant : \dfrac{N.m^2}{kg^2}

Hence, the missing unit of gravitational constant =\dfrac{N.m^2}{kg^2}

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