Question

(iii) Find the charge stored in the capacitor in the given circuit
6 F
HE
100
2012
2V
a. 3 pc
b. 6 °C
C. 8 μο
d. 4 PC​

Answer 1

Answer:

In steady state condition no current flow through the capacitor,

The equivalent resistance is,

R

eq

=10+20=30Ω

The current flow thought the circuit is

i=

30

2

A

The voltage drop across the 10Ω is

V

′

=iR=

30

2

×10=

3

2

V which is equal to the voltage across capacitor.

The charge stored in the capacitor of capacitance, C=6μF

Q=CV

′

=6×10

−6

×

3

2

Q=4μC

The correct option is A.

Answer 2

Answer:

option a is correct

..........