Question

(iii) If one gram of ice at 1 atmospheric pressure and 0° C is converted to 1g of water. Then how
much heat is absorbed by the ice?​

Answer 1

Answer:

We have the latent heat of fusion as 80 cal/g, specific heat of water as 1 cal/g/K and latent heat of vaporization as 540 cal/g. Thus we get the amount of heat required as- heat required to melt ice+heat required to raise the temperature of water from 0 o C to 100 o C + heat required ot vaporize water =mL ice ​ +mCΔT+mL water ​ =(1×80)+(1×1×100)+(540×1)=720 cal

Explanation: