Question

(iii) RP2 + QR2 = PQ?
7. Find the perimeter of the rectangle whose length is 40 cm and a diagonal is 41 cm
o measure 16 cm and 30 cm. Find its perimeter.
TL
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Answer 1

Answer:

Now, in triangle ADC, by Pythagoras theorem (Hypotenuse)2 = (Perpendicular)2 + (Base)2

(AC)2 = (DC)2 + (AD)2

(41)2 = (40)2 + (x)2

1681 = 1600 +(x)2

1681 – 1600 = (x)2

x2 = 81

x = 9 cm

Therefore, breadth of the rectangle = 9 cm

As we know that Perimeter of rectangle = 2(l + b)

= 2(40 + 9)

= 2(49)

= 98 cm

Hence, the perimeter of the rectangle is 98 cm.

Step-by-step explanation:

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