(iii) sin 2A = 2 sin A
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sin2A=2sinA
2sinA.cosA-2sinA =0
2sinA(cosA-1)=0
either 2sinA=0
sinA=0
sinA=sin0°
A= 0°
or cosA -1=0
cosA=1
cosA=cos 0°
A=0° , Answer
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sin2A = 2sinAcosA
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