Question

iii. Ten cards with numbers 1 to 10 written on them are placed in a bag.A card is chosen from the bag
at random. Find the probability of getting
a) the number 7 b) a number less than 3 c) the number 8 d)a number greater than 4​

Answer 1

Given:

☛ Ten cards with numbers 1 to 10 written on them in a bag.

To Find:

☛ Probability of getting:

1. the number 7
2. a number less than 3
3. the number 8
4. a number greater than 4

Solution:

☛ Total possible outcomes = Total no. of cards

➜ Total possible outcomes = 10

1.

Favourable outcomes = 1 { there is only one card with number 7 }

So,

☛ P(E) = favourable outcomes / total possible outcomes

➜ P(E) = 1 / 10

2.

Favourable outcomes = 2 { there are two cards having number less 3 i.e card with 1 and card with 2 }

So,

☛ P(E) = favourable outcomes / total possible outcomes

➜ P(E) = 2 / 10

➜ P(E) = 1/5

3.

Favourable outcomes = 1 { there is only one card with number 8 }

So,

☛ P(E) = favourable outcomes / total possible outcomes

➜ P(E) = 1 / 10

4.

Favourable outcomes = 6 { there are six cards having number greater than 4 }

So,

☛ P(E) = favourable outcomes / total possible outcomes

➜ P(E) = 6 / 10

➜ P(E) = 3/5

Answer 2

A =1,2,3,4,5,6,7,8,9,10

n(A)=10

(a)

a=the number 7

a=7n(a)=1

P(a)=n(a)/n(A) =1/10

(b)

b=less than 3

b=1,2

n(b) =2

P(b)=n(b)/n(A)

=2/10

(c)

c=the number is 8

c=8

n(c)=1

P(c)=n(c)/n(A)

=1/10

(d)

d=a number greater than 4

d=5,6,7,8,9,10

n(d) =6

P(d) =n(d) /n(A)

=6/10

=3/5

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