(iii) The mean proportional between 16 and 4 is
(a) 8
(6) 4
(c) 2
(d) 16
please paste a picture with this question and answer correctly
Answers
=
Step-by-step explanation:
(i) mean proportional between 16 and 4
=\sqrt{16\times4}=
16×4
=\sqrt{64}=
64
= 8
(ii) mean proportional between 3 and 27
=\sqrt{3\times27}=
3×27
=\sqrt{81}=
81
= 9
(iii) mean proportional between 0.9 and 2.5
=\sqrt{0.9\times2.5}=
0.9×2.5
=\sqrt{\frac{9}{10}}\times\sqrt{\frac{25}{10}}=
10
9
×
10
25
=\sqrt{\frac{225}{100}}=
100
225
=\frac{15}{10}=
10
15
= 1.5
(iv) mean proportional between 0.6 and 9.6
=\sqrt{0.6\times9.6}=
0.6×9.6
=\sqrt{\frac{6}{10}}\times\sqrt{\frac{96}{10}}=
10
6
×
10
96
=\sqrt{\frac{576}{100}}=
100
576
=\frac{24}{10}=2.4=
10
24
=2.4
(v) mean proportional between \frac{1}{4}\ and\ \frac{1}{16}
4
1
and
16
1
=\sqrt{\frac{1}{4}\times\frac{1}{16}}=
4
1
×
16
1
=\sqrt{\frac{1}{64}}=
64
1
=\frac{1}{8}=
8
1
Answer:
option (a) 8
is the correct answer
I hope it will help u