Question

iii) the other name for equilateral triangle
ABC is an equilateral triangle. AD is perpendicular to BC and BE is perpendicular
to AC Then show that AABD AACD.​

Answer 1

Step-by-step explanation:

In △ADB and △ADC

AB=AC  (given)

AD=AD  (common side)

∠ADB=∠ADC=90∘  (AsAD⊥BC)

∴△ADB≅△ADC by RHS property.