iii)
(x - 1)(x-2)(x-3)
(x + 1)(x + 2)(x+3)
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here is your answer
Step-by-step explanation:
=>(x+1)(x+2)(x+3)(x−1)(x−2)(x−3)>1
=>(x+1)(x+2)(x+3)(x−1)(x−2)(x−3)−(x+1)(x+2)(x+3)>1
=>(x+1)(x+2)(x+3)x3−3x2+2x−3x2+9x−6−x3−3x2−2x−3x2−9x−6>1
=>(x+1)(x+2)(x+3)−12x2−12>0
=>(x2+1)(x+2)(x−3)(x2−1)<0
=>(x+2)(x+3)x−1<0
=>xϵ(−∞,−3)∪(−2,1).
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Answer:
heres the answer. hope it helps
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