Question

(iii) (x + y,0) = (2,x-y) ordered pairs​

Answer 1

from the Question ,

x + y = 2 ____ eq(1)

and,

x - y = 0

⇒ x = y ___ eq(2)

so , from eq(1) ,

x + y = 2

⇒ y + y = 2

⇒ 2y = 2

⇒ y = 2/2 = 1

hence , x = 1

The values are :

x = 1

y = 1

Answer 2

hope this will help you buddy