Math, asked by guru4829, 1 year ago

iii) x2 - (5-1) x + (18+i) = 0

Answers

Answered by rittikasharma1230059

4

x2 - (5-1) x + (18+i) = 0

=>x2-5x-x+18+i=0

=>x(x-5)-(x-18)+i=0

=>(x-1)(x-18+i)=0

So x-18+i=x-5=>I=18-5=>i=13

Please please please please mark my answer as brainliest.

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