(iii) x² - 6x +k=0
find value of ∆
Answers
Answered by
2
Answer:
Step-by-step explanation:
Attachments:
Answered by
0
b^2-4ac
a=1 b=6
c=k
6^2-4(1)(k)
12-4(k)=0
-4(k)=-12
K=-12/-4
K=3
a=1 b=6
c=k
6^2-4(1)(k)
12-4(k)=0
-4(k)=-12
K=-12/-4
K=3
Similar questions