Question

(iii) Zeroes of the polynomial x² - 5x + 6
Solution:​

Answer 1

Answer zeroes of x are 2 and 3

Step-by-step explanation:

let x2 - 5x + 6 = 0

sum= -5 and product 6

so numbers are - 3 and -2

therefore eq becomez

x2 -3x-2x+6 = 0

x(x-3)-2(x-3) = 0

(x-2) * (x-3) = 0

x-3 = 0.

x = 3

x-2 =0

x= 2

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Answer 2

Step-by-step explanation:

$\bf{\blue{\underline{question \: : - }}}$

Given,

$\boxed{\bold{ {x}^{2} - 5x + 6}}$

To Find,

$\boxed{\bf{zero \: of \: the \: polynomial}}$

$\bold{\star{\pink{\underline{\underline{solution \: : - }}}}}$

$\implies{\bf{ {x}^{2} - 3x - 2x + 6 = 0}}$

$\bf {\implies{\ x( x - 3) - 2(x - 3) = 0}}$

$\implies{\bf{(x - 2) \: (x - 3) = 0}}$

SO,

X = 2 X =3

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There for value of x²-5x+6 is zero are 2 and 3

$\boxed{\bf{sum \: of \: zeroes = 3 + 2 = \frac{5}{1}}} \\ \\ = \frac{ - (coefficient \: of \: {x}) }{(coefficient \: of \: {x}^{2})}$

$\boxed{\bf{products \: of \: zeroes = 3 \times 2 = \frac{6}{1}}} \\ \\ \frac{constant \:term }{(coefficient \: of \: {x}^{2})}$

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