Math, asked by karthikreddy0502, 5 months ago

(iii) Zeroes of the polynomial x² - 5x + 6
Solution:​

Answers

Answered by vkadithyan
0

Answer zeroes of x are 2 and 3

Step-by-step explanation:

let x2 - 5x + 6 = 0

sum= -5 and product 6

so numbers are - 3 and -2

therefore eq becomez

x2 -3x-2x+6 = 0

x(x-3)-2(x-3) = 0

(x-2) * (x-3) = 0

x-3 = 0.

x = 3

x-2 =0

x= 2

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Answered by Anonymous
13

Step-by-step explanation:

  \bf{\blue{\underline{question \:  :  - }}}

Given,

 \boxed{\bold{ {x}^{2}  - 5x + 6}}

To Find,

 \boxed{\bf{zero \: of \: the \: polynomial}}

 \bold{\star{\pink{\underline{\underline{solution \:  :  - }}}}}

 \implies{\bf{ {x}^{2}   - 3x - 2x + 6 = 0}}

 \bf {\implies{\ x( x - 3) - 2(x - 3) = 0}}

 \implies{\bf{(x - 2) \: (x - 3) = 0}}

SO,

X = 2 X =3

There for value of -5x+6 is zero are 2 and 3

 \boxed{\bf{sum \: of \: zeroes = 3 + 2 =  \frac{5}{1}}}  \\  \\  =  \frac{ - (coefficient \: of \:  {x}) }{(coefficient \: of \:  {x}^{2})}

 \boxed{\bf{products \: of \: zeroes = 3 \times 2 =  \frac{6}{1}}} \\  \\   \frac{constant \:term }{(coefficient \: of \:  {x}^{2})}

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