Math, asked by kahkashan1005, 4 months ago

Ikram invests £7000 in a savings account paying compound interest for 2 years.
In the first year, the rate of interest is x%.
At the end of the first year the value of Ikram's investment is £7273
In the second year, the rate of interest is x/3 %
What is the value of Ikram's investment at the end of the 2 years?​

Answers

Answered by amitnrw
4

Given : Ikram invests £7000 in a savings account paying compound interest for 2 years.

In the first year, the rate of interest is x%.

At the end of the first year the value of Ikram's investment is £7273

In the second year, the rate of interest is x/3 %

To Find : What is the value of Ikram's investment at the end of the 2 years

Solution:

At the end of the first year the value of Ikram's investment is £7273

P = 7000

R = x  % per annum

n  = 1

A = 7273

A = P(1 + R/100)ⁿ

=> 7273 = 7000(1  + x/100)¹

=> 273  = 70x

=> x = 273/70

second year, the rate of interest is x/3 %

= 91/70 %

P = 7273

R = 91/70 %

n = 1

A = ?

A =  7273 (1  + 91/7000)¹

=> A = 7,367.55

value of Ikram's investment at the end of the 2 years  = £ 7,367.55

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