Il 3rd
A.P
is 18 and 7th term is
terms of
9th teren
find
10
Answers
Answered by
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- 3rd term of AP is 18
- it can be written as a8=a+(7-1)d=18
- a+6d=18........(1)
- 7th term of AP is = 10 term of the AP
- 7th term = a+(6-1)d
- a+5d.......(2)
- 9th term =a+(8-1)d
- a+7d.......(3)
- from 2 and 3
- 2a+8d=0..........(4)
- solving 1 and 4
- a+6d=18.......(1)×2
- 2a+8d=0........(4)×1
- 2a+12d=36-2a+8d
- we get
- 4d=36
- d=8
- by substitute d=8 In equ 1
- a=-30
- 10th term =a+(9-1)d
- -30+8×8
- -30+64
- +34
- ●{a10=34}
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