Question

Illustrate law of multiple proportion using the oxides of a metal containing 78.7% and 64.5% of the metal

Answer 1

Answer:

%of The metal in 1st metal oxide is 78.7%,then Oxygen is 21.3%

Explanation:

In the 2nd case the metal is64.5%,then the oxygen is 35.5% ,in the 1st compound the no of parts of oxygen is 21.3/78.7=0.27parts,the no parts of oxygen in 2nd compound is 35.5/64.5=0.55parts of oxygen ,then the ratioof masses of oxygen that combines is0.27:055=1:2

I hope that you understand well!!!!