Question

ILLUSTRATIVE NUMERICALS
50
in instrument has 20 divisions en vernier scale which coincide with 19 divisions on the main seale:
If one centimetre on the main scale is divided into 20 parts, find its least count.
cm = 0.05 cm​

Answer 1

Answer:

See below.

Explanation:

For least count of any instrument, we have a simple expression,

Least Count = ( Value of smallest division on main scale ) / ( No of divisions on vernier scale )

For the given question, we have the number of divisions on vernier scale as 20. The smallest value which can be measured by the main scale is 1/20 cm which makes 0.05 cm.

Now, the least count is,

$L.C = \frac{0.05}{20} = 0.0025 \ cm^{-1}$