Question

Two sitar strings A and B are producing sound of frequency v and v-∆v respectively what is beat frequency?

How should tension in string b be changed to make beats disappear justify?

Answer 1

Answer:

Beat frequency of the two sitar strings is given as

$f_{beat} = \Delta \nu$

To disappear the beats we need to increase the tension in sitar string B

Explanation:

As we know that Beat Frequency is the difference in the frequency of two sources when two sources of slightly different frequencies

It is the number of maximum intensity observed in 1 second times when two sources of difference frequency sound together

so here we know that

$\nu_1 = \nu$

$\nu_2 = \nu - \Delta \nu$

now beat frequency is given as

$f_{beat} = (\nu) - (\nu - \Delta \nu)$

$f_{beat} = \Delta \nu$

Now in order to make the beats ZERO we need to increase the frequency of wire B

so we know that

$f = \frac{N}{2L}\sqrt{\frac{T}{\rho A}}$

so here in order to increase the frequency we need to increase the tension of the string.

#Learn

Topic : Beats

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