Math, asked by kiran7465, 1 year ago

im struggling to solve this plz help me ​

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Answered by shadowsabers03
1

       

\mathfrak{Hey\ mate!!!}

\cos 60\textdegree=\frac{1}{2} \\ \\ \sec 30\textdegree=\frac{2}{\sqrt{3}} \\ \\ \tan 45\textdegree=1

\Rightarrow\ \boxed{\frac{5\cos^2 60\textdegree+4\sec^230\textdegree-\tan^245\textdegree}{\sin^230\textdegree+\cos^230\textdegree}} \\ \\ \\ \Rightarrow\ \boxed{\frac{5(\frac{1}{2})^2+4(\frac{2}{\sqrt{3}})^2-1^2}{1}}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \boxed{\sin^2\theta+\cos^2\theta=1} \\ \\ \\ \Rightarrow\ \boxed{5 \times \frac{1}{4}+4 \times \frac{4}{3}-1} \\ \\ \\ \Rightarrow\ \boxed{\frac{5}{4}+\frac{16}{3}-1} \\ \\ \\ \Rightarrow\ \boxed{\frac{15}{12}+\frac{64}{12}-\frac{12}{12}}

\Rightarrow\ \boxed{\frac{15+64-12}{12}} \\ \\ \\ \Rightarrow\ \boxed{\bold{\frac{67}{12}}}

$$\sf{Hope this helps. Plz ask me if you have any doubt on my answer. }

$$Thank you. :-))

\mathfrak{\#adithyasajeevan}

   


kiran7465: love u ❤ bro. you are the perfect maths companion for me
shadowsabers03: Thank you. Thanks a lot. :-))
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