Question

Image formed by a concave mirror of focal length 6 cm, is 3 times of the object, then the distance of object from mirror is(a) – 4 cm(b) 8 cm(c) 6 cm(d) 12 cm

Answer 1

Hey !!

-> 3 times of the object. So the magnification is ±3.

So, therefore

            Focal length will be -6 cm.

Magnification formula,

            m =  f/f - u

Now,

       m = - 3 ( Real image )

Substituting the values in the magnification formula,

      - 3 =  -6 / -6 - u    

   u = -8 cm        

m = 3 (Virtual image)

 => 3 = - 6 / - 6 - u  

=> u = -4 cm

Option (A) -4 cm

Good luck !!

 

Answer 2

HOPE THIS ANSWER HELPS YOU
MARK AS BRAINLIEST ✌✌
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