Question

Image of an obejct approaching a convex mirror of radius of curvature 20 m along its optical axis is

observed to move from

25 50 mto m

3 7

in 30 s. The speed of the object in

1 kmh

is​

Answer 1

Answer:

hope it will helpful

Explanation:

Let us first find the initial position of the object .

v1 + u1 = f1

253 + u1 = 101

u1 = 50−1

u=−50

Now let us find the final position of the object :

v1 + u1

= f1507 +u 1

=101

u1 = 50−2

u=−25

Therefore the shift in object is : 50-25 = 25 m

The time taken for this shift = 30 s

Speed = 30s25m

=hr3Km