Imagine a girl of mass 50 kg standing on pencil heels, each of area of cross-section of 1 cm², and an elephant of mass 2000 kg and foot area of 150 cm² standing on floor. Find the preassure exerted by each of them assuming acceleration due to gravity as 10 m/s². Which of the two exerts more pressure on floor ?
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hey mate
here is ans
PRESSURE= FORCE/ AREA
P= mass*acc/area
case 1 girl
m= 50kg
a= 1cm^2
p = m* g/ area. ( g is equal to ac)
p = 50*10/1
= 500Nm^2
case 2 elephant
m= 2000kg
a= 150 cm^2
p = m*g/a
= 2000*10/150
2000/15
133.3 Nm^2
according to both cases
girl pressure is more than the elephant
hope it may help u
here is ans
PRESSURE= FORCE/ AREA
P= mass*acc/area
case 1 girl
m= 50kg
a= 1cm^2
p = m* g/ area. ( g is equal to ac)
p = 50*10/1
= 500Nm^2
case 2 elephant
m= 2000kg
a= 150 cm^2
p = m*g/a
= 2000*10/150
2000/15
133.3 Nm^2
according to both cases
girl pressure is more than the elephant
hope it may help u
KrishnaFoujdar:
thanxxx
in which class u r ....??
brother iam in 12 class
thanxxx
it ok bro
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