Imagine. a new planet having the density as that of. earth but it's. 3times bigger than earth in size. If actual acceleration due to gravity on the surface of earth is g and of new planet is g' then
a. g'=3g
b. g'=9g
c. g'=g/9
d. g'=27g
Answers
Answered by
11
i think the answer will be A 3g
as f=mg
if m=3 then,
=3g
as f=mg
if m=3 then,
=3g
Answered by
18
hello frnd...
we know that,
g=GM/R^2
= G4/3πR^3d/R^2
Rplanet = 3R
Hence g' = 3g
we know that,
g=GM/R^2
= G4/3πR^3d/R^2
Rplanet = 3R
Hence g' = 3g
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