Question

Implement a circuit of the function, F = (A'B')' + D'(B + C)

Answer 1

Answer:

[math]F=A(B+C'D)+BC'=AB+ AC'D+BC'[/math]

[math]F=\overline{\overline{AB+ AC'D+BC'}}[/math]

Using Demorgans thorem,

[math]F=\overline{\overline{(AB)})\; \overline{(AC'D})\;\overline{(BC')}}[/math]

To be precise,

[math]F=\overline{\overline{(AB)}\; \overline{(A\overline{C}\;D)}\;\overline{(B\;\overline{C}})}[/math]