Question

important question from coordinate geometery class 10​

Answer 1

Answer:

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Answer 2

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Question 2.

Question 2.If the points A(x, 2), B(-3, 4) and C(7, -5) are collinear, then find the value of x. (2014D)

Question 2.If the points A(x, 2), B(-3, 4) and C(7, -5) are collinear, then find the value of x. (2014D)Solution:

Question 2.If the points A(x, 2), B(-3, 4) and C(7, -5) are collinear, then find the value of x. (2014D)Solution:When the points are collinear,

Question 2.If the points A(x, 2), B(-3, 4) and C(7, -5) are collinear, then find the value of x. (2014D)Solution:When the points are collinear,x1(y2 – y3) + x2(y3 – y1) + x3(y1 – y2) = 0

Question 2.If the points A(x, 2), B(-3, 4) and C(7, -5) are collinear, then find the value of x. (2014D)Solution:When the points are collinear,x1(y2 – y3) + x2(y3 – y1) + x3(y1 – y2) = 0x(-4 – (-5)) + (-3)(-5 – 2) + 7(2 – (-4)) = 0

Question 2.If the points A(x, 2), B(-3, 4) and C(7, -5) are collinear, then find the value of x. (2014D)Solution:When the points are collinear,x1(y2 – y3) + x2(y3 – y1) + x3(y1 – y2) = 0x(-4 – (-5)) + (-3)(-5 – 2) + 7(2 – (-4)) = 0x(1) + 21 + 42 = 0

Question 2.If the points A(x, 2), B(-3, 4) and C(7, -5) are collinear, then find the value of x. (2014D)Solution:When the points are collinear,x1(y2 – y3) + x2(y3 – y1) + x3(y1 – y2) = 0x(-4 – (-5)) + (-3)(-5 – 2) + 7(2 – (-4)) = 0x(1) + 21 + 42 = 0x + 63 = 0 ∴ x = -63

Question 2.If the points A(x, 2), B(-3, 4) and C(7, -5) are collinear, then find the value of x. (2014D)Solution:When the points are collinear,x1(y2 – y3) + x2(y3 – y1) + x3(y1 – y2) = 0x(-4 – (-5)) + (-3)(-5 – 2) + 7(2 – (-4)) = 0x(1) + 21 + 42 = 0x + 63 = 0 ∴ x = -63

Question 2.If the points A(x, 2), B(-3, 4) and C(7, -5) are collinear, then find the value of x. (2014D)Solution:When the points are collinear,x1(y2 – y3) + x2(y3 – y1) + x3(y1 – y2) = 0x(-4 – (-5)) + (-3)(-5 – 2) + 7(2 – (-4)) = 0x(1) + 21 + 42 = 0x + 63 = 0 ∴ x = -63 Question 3.

Question 2.If the points A(x, 2), B(-3, 4) and C(7, -5) are collinear, then find the value of x. (2014D)Solution:When the points are collinear,x1(y2 – y3) + x2(y3 – y1) + x3(y1 – y2) = 0x(-4 – (-5)) + (-3)(-5 – 2) + 7(2 – (-4)) = 0x(1) + 21 + 42 = 0x + 63 = 0 ∴ x = -63 Question 3.For what value of k will k + 9, 2k – 1 and 2k + 7 are the consecutive terms of an A.P.? (2016OD)

Question 2.If the points A(x, 2), B(-3, 4) and C(7, -5) are collinear, then find the value of x. (2014D)Solution:When the points are collinear,x1(y2 – y3) + x2(y3 – y1) + x3(y1 – y2) = 0x(-4 – (-5)) + (-3)(-5 – 2) + 7(2 – (-4)) = 0x(1) + 21 + 42 = 0x + 63 = 0 ∴ x = -63 Question 3.For what value of k will k + 9, 2k – 1 and 2k + 7 are the consecutive terms of an A.P.? (2016OD)Solution:

Question 2.If the points A(x, 2), B(-3, 4) and C(7, -5) are collinear, then find the value of x. (2014D)Solution:When the points are collinear,x1(y2 – y3) + x2(y3 – y1) + x3(y1 – y2) = 0x(-4 – (-5)) + (-3)(-5 – 2) + 7(2 – (-4)) = 0x(1) + 21 + 42 = 0x + 63 = 0 ∴ x = -63 Question 3.For what value of k will k + 9, 2k – 1 and 2k + 7 are the consecutive terms of an A.P.? (2016OD)Solution:As we know, a2 – a1 = a3 – a2

Question 2.If the points A(x, 2), B(-3, 4) and C(7, -5) are collinear, then find the value of x. (2014D)Solution:When the points are collinear,x1(y2 – y3) + x2(y3 – y1) + x3(y1 – y2) = 0x(-4 – (-5)) + (-3)(-5 – 2) + 7(2 – (-4)) = 0x(1) + 21 + 42 = 0x + 63 = 0 ∴ x = -63 Question 3.For what value of k will k + 9, 2k – 1 and 2k + 7 are the consecutive terms of an A.P.? (2016OD)Solution:As we know, a2 – a1 = a3 – a22k – 1 – (k + 9) = 2k + 7 – (2k – 1)

Question 2.If the points A(x, 2), B(-3, 4) and C(7, -5) are collinear, then find the value of x. (2014D)Solution:When the points are collinear,x1(y2 – y3) + x2(y3 – y1) + x3(y1 – y2) = 0x(-4 – (-5)) + (-3)(-5 – 2) + 7(2 – (-4)) = 0x(1) + 21 + 42 = 0x + 63 = 0 ∴ x = -63 Question 3.For what value of k will k + 9, 2k – 1 and 2k + 7 are the consecutive terms of an A.P.? (2016OD)Solution:As we know, a2 – a1 = a3 – a22k – 1 – (k + 9) = 2k + 7 – (2k – 1)2k – 1 – k – 9 = 2k + 7 – 2k + 1

Question 2.If the points A(x, 2), B(-3, 4) and C(7, -5) are collinear, then find the value of x. (2014D)Solution:When the points are collinear,x1(y2 – y3) + x2(y3 – y1) + x3(y1 – y2) = 0x(-4 – (-5)) + (-3)(-5 – 2) + 7(2 – (-4)) = 0x(1) + 21 + 42 = 0x + 63 = 0 ∴ x = -63 Question 3.For what value of k will k + 9, 2k – 1 and 2k + 7 are the consecutive terms of an A.P.? (2016OD)Solution:As we know, a2 – a1 = a3 – a22k – 1 – (k + 9) = 2k + 7 – (2k – 1)2k – 1 – k – 9 = 2k + 7 – 2k + 1k – 10 = 8 ∴ k = 8 + 10 = 18

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