Question

Imran has a piece of metal wire of resistance 40ohm which is drawn out so that its length is increased to twice its original length. Calculate the resistance of a wire in the new situation?​

Answer 1

Answer:

4×40=160Ω

Explanation:

R=ρl/A

R=ρl/(v/l){v is volume i.e. volume=area × length}

R=ρl²/v

as volume and ρ (resistivity) are constant here.

R ∝ l²

Answer 2

Answer:

160 ohm

Explanation:

i hope you would get your answer