Question

In 1 3 gives 3a the reaction the initial concentration of a3 is a mole per litre if x is degree of dissociation of a 3 the total number of moles at equilibrium will be

Answer 1

Answer:

$A_{3}(g)<=>3A_{(g)}$

Initial:Let 'X' moles dissociate

At equation: a-x       3x

At equilibrium: a-aα     3aα

Then the total number of moles at equilibrium=a-aα+3aα=a+2aα

=a(1+2α)  

Answer 2

Answer:a+2ax

Explanation:pls refer the attached pic HOPE IT HELPS YOU

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