Question

In 10 years a will be twice as old as b was 10 ago if a now 9 years older than b the parentage age b

Answer 1

Answer:

Step-by-step explanation:

Lets denote their current ages by a years and b years.

After 10 years, A would be a+10 years old and B would be b+10 years old.

After 10 years, a+10=2∗(b+10)

or a−2∗b=10 ← Lets call this Equation 1

5 years ago, their ages were a - 5 and b - 5 respectively.

or a−5=3∗(b−5)

a−3∗b=−10 ← lets call this Equation 2

Subtracting Equation 2 from Equation 1, we get:

a−2∗b−(a−3∗b)=10−(−10)

or b = 20

From Equation 1, we know that a = 10 + 2*b = 10 + 40 = 50

Therefore A is 50 years old and B is 20 years old today.