Question

In 100 seconds, 300 ml of nitrogen diffuse
through a porous partition.How long will 400
ml of Carbon dioxide take to diffuse through the same
partial under similar conditions? ​

Answer 1

Explanation:

The rate of diffusion is volume diffused per unit time and is inversely proportional to the square root of molar mass.

r

′

r

=

V

′

t

Vt

′

=

M

M

′

Here, r, V, t, and M are the rate of diffusion, the volume diffused, the time taken for diffusion and the molar mass of SO

2

and r', V', t' and M' are the rate of diffusion, the volume diffused, the time is taken for diffusion and the molar mass of O

2

respectively.

Substitute values in the above equation

V

′

×60

20×30

=

64

32

V

′

=14.14 L.

Hence, a volume of O

2

diffused under similar conditions in 30 seconds will be 14.14 L.