Question

in 1s a particle goes from point a to point b moving in a semicircle the magnitude of angular velocity is

Answer 1

we know that ,
the rate of change in angular displacement is equal to the angular velocity

and we also know that ,
Ɵ = l/r

if the particle moves full circle then distance covered by it is 2πr (circumstance)
if it is moves half of that then distance moved is 2πr/2 = πr(arc)

Ɵ = πr/r

Ɵ = π

the angle between point A and B is π radian
ω = Ɵ/t
ω = π/1
ω = π rad/s

Therefore magnitude of the angular velocity is π rad/s