Question

in 2???s complement number system the range of values for 16-bit numbers is given as

Answer 1

The range of numbers that can be represented in n-bits is:

= > -(2^n-1).......(2^n-1) - 1

Now,

Here we need to calculate 16-bit number:

= > -(2^16 - 1).....(2^16 - 1) - 1

= > -(2^15).....(2^15)-1

= > -32768....32767.

Therefore, 16-bits gives us the range of [-32768,32767].

Hope this helps!