Question

In 240 ml of water and dettol the ratio of the volume of water and dettol is 1:3 if 60 ml of water is added to it, let's find the ratio of the volume of water and dettol in new mixture​

Answer 1

Answer:

Let the amount of water & dettol be n & 3n.

$\underline{\bigstar\:\:\textsf{According to the Question :}}$

$:\implies\tt Water+Dettol=Total\:Mixture\\\\\\:\implies\tt n+3n=240\:ml\\\\\\:\implies\tt 4n=240\:ml\\\\\\:\implies\tt n=\dfrac{240\:ml}{4}\\\\\\:\implies\tt n=60\:ml$

$\rule{160}{1}$

$\underline{\bigstar\:\:\textsf{Ratio of New Mixtures :}}$

$\dashrightarrow\tt\:\:(Water+Added\: Amount):Dettol\\\\\\\dashrightarrow\tt\:\:(n+60\:ml):3n\\\\\\\dashrightarrow\tt\:\:(60\:ml+60\:ml):3(60\:ml)\\\\\\\dashrightarrow\tt\:\:120\:ml:180\:ml\\\\{\scriptsize\qquad\bf{\dag}\:\:\textsf{Dividing both term by 60 ml.}}\\\\\dashrightarrow\:\:\underline{\boxed{\textsf{\textbf{2 : 3}}}}$

⠀

$\therefore\:\underline{\textsf{New ratio of water and dettol is \textbf{2 : 3}}}.$

Answer 2

AnswEr:-

New ratio of volume in new mixture= 2 : 3

$\rule{200}{1}$

Given :-

☛ Total mixture = 240 ml

☛ Ratio of water & Dettol = 1 : 3

To find:-

☛ New ratio of water & dettol if 60 ml of water is mixed = ?

Solution:-

Let the volume of water be y and volume of dettol be 3y.

According to question:-

⇒ y + 3y = 240

⇒ 4y = 240

⇒ y = 240/4

⇒ y = 60 ml

⋆ VOLUME OF WATER & DETTOL:-

↠ Volume of water = y = 60 ml

↠ Volume of dettol = 3y = 3(60) = 180 ml

Now ratio in new mixture:-

⇒New volume of water = 60 + 60 ml

⇒ New volume of water = 120 ml

And,

⇒ Volume of dettol = 180 ml

⋆ NEW RATIO:-

⇒ Ratio of water & dettol = 120 : 180

• Dividing both by 60 :-

⇒ New ratio of water & dettol = 2 : 3

Therefore,

New ratio of volume of water & dettol in new mixture = 2 : 3 .