In 25°C temperature and 2 air pressure 2 lit, to make N2( g) how much NH4Cl is needed??
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Answer:
NH4Cl(s)→1mol1molNH3(g)+HCl(g)
∵53.5gNH4Cl give 1 mol NH3
∴26.25gNH4Cl will give 53.51×26.25moleNH3 =0.5mole
PV=nRT
1×V=0.5×0.0821×300
V=12.315litreample
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