Question

in 2nd question first find L. C. M. then find value of M and N.
Right answer will be Mark as brainliest answer
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Answer 1

Answer:

m = 2, n = 1

Step-by-step explanation:

Find HCF:

Euclid's division lemma:

117 = 65 * 1 + 52

65 = 52 * 1 + 13

52 = 13 * 4 + 0.

Here, remainder is 0. Therefore, HCF of 65 and 117 is 13.

Find LCM:

Prime Factorization of 65 = 5 * 13.

Prime factorization of 117 =  13 * 3 * 3.

LCM(65,117) = 5 * 13 * 3 * 3

                    = 585.

Find m,n:

13 = 65 - 52 * (1)

13 = 65 - (117 - 65 * 1) * 1

13 = 65 - 117 + 65 * 1

13 = 65 * 2 + (-1) * 117

13 = 65 * 2 - 1 * 117

It is the form of 65m - 117n.

Therefore, m = 2, n = 1.

Hope it helps!