Question

In 3.2 gm of methane, determine the number of

a) Methane molecules

b) C atoms

c) H atoms

d) Total number of atoms

e) Total number of protons

f) Total number of electrons

g) Total number of neutrons

Answer 1

Answer:

a) 1.2046*10^23 molecules

b) & c) 1 C atom and 4 H atoms

d) ,e) & f)

10 proton, 10 electron and 6 neutrons.

Explanation:

Given in the picture.

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Answer 2

Given:

Mass of methane = 3.2 gm

To Find:

Number of:

(a) Methane molecules

( b) C atoms

(c) H atoms

(d) Total number of atoms

(e) Total number of protons

(f) Total number of electrons

(g) Total number of neutrons

Calculation:

(a) No of moles of methane = 3.2/16 = 0.2

⇒ No of  Methane molecules  = 0.2 × 6.022 × 10²³

⇒ No of  Methane molecules  = 1.2044 × 10²³

(b) No of C atoms in 1 methane molecule = 1

⇒ No of C atoms in 1.2044 × 10²³ methane molecules = 1 × 1.2044 × 10²³

⇒ No of C atoms = 1.2044 × 10²³

(c) No of H atoms in 1 methane molecule = 4

⇒ No of H atoms in 1.2044 × 10²³ methane molecules = 4 × 1.2044 × 10²³

⇒ No of H atoms = 4.8176 × 10²³

(d) Total no of atoms = No of C atoms + No of H atoms

⇒ Total no of atoms = 1.2044 × 10²³ + 4.8176 × 10²³

⇒ Total no of atoms = 6.022 × 10²³

(e) No of protons in 1 methane molecule = 6 + 4 = 10

⇒ Total no of protons in 6.022×10²³ methane molecules = 6.022×10²³ × 10

⇒ Total no of protons = 6.022 × 10²⁴

(f) Total no of electrons = Total no of protons

⇒ Total no of electrons = 6.022 × 10²⁴

(g) No of neutrons in 1 CH₄ molecule = 6  (as H do not have any neutrons)

⇒ Total no of neutrons in 6.022×10²³ methane molecules = 6.022×10²³ × 6

⇒ Total no of neutrons = 3.6132 × 10²⁴