Math, asked by noorjahanarmin5301, 4 months ago

in 5 years, The ratio of Mr. X's age to his brother will be 1:2. 5 years ago the ratio was 1:4. how old is Mr x?

Answers

Answered by sanaaliafa
0

Answer:

10 years old

Step-by-step explanation:

We know that the ratio goes from 1:4 to 1:2 in 10 years.

We find out the LCM of 4, 2 and 10, which is 20.

We now know that Mr.X's brother was 20 five years ago.

Because we know his brother was 20, we divide 20 by 4 (The ratio was 1:4) to get Mr.X's age, which was 5.

Therefore we know Mr.X was 5 five years ago.

All we have to do is add on five years to 5 to get to the present, which is 10.

Mr.X's current age is 10.

Answered by joelpaulabraham
3

Answer:

Mr.X's present age is 10 years.

Step-by-step explanation:

Let the present age of Mr.X's be 'x' and his brother's present age be 'y' years old.

Now,

In 5 years,

Mr.X's age = (x + 5)

Brother's age = (y + 5)

According to the Question,

(x + 5) : (y + 5) :: 1 : 2

We know that,

Product of extremes = Product of means

2(x + 5) = 1(y + 5)

2x + 10 = y + 5

2x - y = 5 - 10

2x - y = -5

So,

y = 2x + 5 ---- 1

Also,

5 years age,

Mr.X's age = (x - 5)

Brother's age = (y - 5)

According to the Question,

(x - 5) : (y - 5) :: 1 : 4

Now,

Product of extremes = Product of means

4(x - 5) = 1(y - 5)

4x - 20 = y - 5

4x - y = 20 - 5

4x - y = 15

From eq.1 we get,

4x - (2x + 5) = 15

4x - 2x - 5 = 15

2x = 15 + 5

2x = 20

x = 20/2

x = 10

Hence,

Mr.X's present age is 10 years.

Hope it helped and believing you understood it........All the best

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