Question

In 7 days a machine cleans 5.6 ×10⁷ kg wt of iron orn . How much iron ore will it clean in 45 days?

Answer 1

Step-by-step explanation:

Amount of iron ore it cleans in 7 days = 5.6×10^7 kg wt

Amount of iron ore it will clean in 1 day = (5.6×10^7)/7 kg wt

Therefore,

Amount of iron ore it will clean in 45 days =

(5.6 × 10^7 × 45)/7 kg wt

= (252 × 10^7) / 7 kg wt

= 36 × 10^7 kg wt

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