In 8 days a machine cleans 6.4 ×10^7 kg weight of iron ore. How much iron ore will it clean in 44 days
Answers
Answered by
3
Answer:
using unitary method,
Step-by-step explanation:
In 8 days, it cleans 6.4 × 10^7 kg
In 1 day, it cleans 6.4 × 10^7 / 8 kg
In 44 days, it cleans 6.4 × 10^7 × 44 / 8k kg
= 35.2 × 10^7 kg iron ore
Answered by
2
Step-by-step explanation:
D1/W1=D2/W2
M2=D2*W1/D1
=44*6.4*10^7/8
=352*10^8
=35.2*10^7kg
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