Math, asked by Kushangbaudh, 1 year ago

In 8 hours ,Abhimanyu walk 1 km more than Sadanand does in 10 hours and 14 hours, Sadanand walks 4 km more than Abhimanyu walk in 10 hours find the speed of walking in kilometre per hour

Answers

Answered by Kundank
8
just use the equation given in question

Speed of Abhi = 4.5km/hr
speed of Sada = 3.5km/hr
Attachments:
Answered by vaduz
11

Answer: abhimanyu is 4.5 km per hour

sadanand is 3.5 km per hour


Step-by-step explanation:

let speed of abhimanyu is x km per hour and sadanand is y km per hour.

as we know that

speed = \frac{distance }{time}

according to question

In 8 hours ,Abhimanyu walk 1 km more than Sadanand does in 10 hours

x*8 - y* 10 = 1

8x - 10y = 1 - - - - - - 1

and

14 hours, Sadanand walks 4 km more than Abhimanyu walk in 10 hours

y*14 - x*10 = 4

10x - 14y = - 4 - - - - - - - 2

by solving eq 1 and 2

we get

x= 4.5

y= 3.5

so speed of abhimanyu is 4.5 km per hour and sadanand is 3.5 km per hour


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