In 90 g of 20% (w/w) aqueous salt solution 10 g more water is added. Calculate the final concentration (w/w%) of the solution.
Answers
Answered by
19
Answer:
initially:20= 90 / 90 + x × 100
20/100=90/90+x
90+x=5(90)
90+x=450
x=450-90
x=360 gm water
......now more 10 gm water is added so
360+10= 370gm
..(w/W)%= 90/370+90 ×100
=90/460×100
=900/46= 19.56%...plz comment if u liked answer
Answered by
1
Given:
The mass of solution = 90 gm
The w/w % of aqueous salt solution = 20 %
The mass of water added = 10 gm
To Find:
The final concentration of the solution.
Calculation:
- The mass of salt in the given solution, w = 90 × (20/100) = 18 gm
- After adding water, the final mass of the given solution = 90 + 10 = 100 gm
- The final mass % of the solution = (18/100) × 100
⇒ w/w % = 18 %
- So, the final concentration of the solution is 18 % (w/w).
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