Question

In 90 grams of glucose calculate
1. Number of moles glucose
2. Number of molecules of glucose
3. Mass of one glucose molecules
4. Number of C atoms
5. Number of H atoms

Answer 1

Answer:

1. .5 moles

Explanation:

formula of glucose =C6h12O6

mass of C =12*6=72

mass of H =1*12=12

mass of O =16*6=96

add the molar mass = 72+12+96=180

number of moles = given mass/molar mass

=90/180

= .5

Answer 2

$\sf{:::\implies Formula \: for \: finding \: number \: of \: moles}$

$\sf{ \looparrowright No. \: of \: moles = \frac{given \: mass}{molar \: mass} }$

$\sf{ \looparrowright No. \: of \: moles = \frac{given \: particles}{Avogrado's \: constant} }$

$\sf{ ::: \implies Solution}$

$\sf{ \hookrightarrow Molecular \: mass \: of  \: C_6H_{12}O_6 }\\ \sf{=(12×6)+12+(16×6) = 180u}$

$\sf{1) No. \: of \: moles = \frac{90}{180} = 0.5 \: moles}$

$\sf \footnotesize{2)No. \: of \: molecules = Avogrado's \: constant \times no. \: of \: moles}$

$\sf {No. \: of \: molecules = 6.022 \times {10}^{23} \times 0.5}$

$\sf {No. \: of \: molecules = 3.011 \times {10}^{23} }$

$\sf{ 3)Mass \: of  \: 1 \: molecule\: C_6H_{12}O_6 }\\ \sf{=(12×6)+12+(16×6) = 180u}$

$\sf{4)Number \: of \: C \: atoms = 6 \times 90 = 540}$

$\sf{5)Number \: of \: H \: atoms = 12 \times 90 = 1080}$